PHP / Javascript nefuguje odosielanie

[MichalPecko89]

Zdar
V kode je toto

Kód: [Vybrat]

<form name="raise" action="index.php?go=forms/frm_new_fill.php" method="POST">
     
        <table id="tab_logic" style="background-color: #c0c0c0;text-align:center">
        <thead>
<tr>
<th scope="col">None</th>
<th scope="col">Part number</th>
<th scope="col">Location</th>
<th scope="col">Quantity</th>
<th scope="col">Reason</th>
<th scope="col">Notes</th>

</tr>
    </thead>
    <tbody>
   
</tbody>             
</table>
           
                    <div class="buttons">
                        <button type="submit" name="new" class="positive" onClick="submitLoader();">
                            <img src="Assets/images/apply2.png" width="16" height="16" alt=""/>
                            Submit
                        </button>
                    </div><div name="submitLoader" id="submitLoader" style="float:left"></div>
           
                    <div class="buttons">
                        <button type="reset" name="new" class="negative">
                            <img src="Assets/images/cross.png" width="16" height="16" alt=""/>
                            Reset
                        </button>
                    </div>
               
    </form>

s scripte toto

<script>
$(document).ready(function() {
  var i = 0;
  var j = 0;
  var code = '<?php give_me_reason_list();  ?>';




  $("#add_row").click(function() {
  $('tr').find('input').prop('disabled',true)
    j = i;
 
    $('#addr' + i).html(""+(j+1)+ "<td><input type='radio' name='plusminus" + j + "' id='plusminus" + j + "' value='1' onClick='activateReasons(" + j + ");' required/>&nbsp;+<BR/><input type='radio' name='plusminus" + j + "' id='plusminus" + j + "' value='2' onClick='activateReasons(" + j + ");'/>&nbsp;&nbsp;-<input type='hidden' name='value" + j + " id='value" + j + "' value=''><input type='hidden' name='curr" + j + "' id='curr" + j + "' value=''><input type='hidden' name='converted" + j + "' value=''></td><td style='text-align:left'><input type='text' name='part_no" + j + "' id='part_no" + j + "' value='' onBlur='getDescription(" + j + ");' required/><br/><div id='description" + j + "' style='text-align:left'></div><div id='price" + j + "' style='text-align:left'></div><div id='gbp_price" + j + "' style='text-align:left'></div></td><td><select name='location" + j + "' id='location" + j + "'><option value='S001'>Main Warehouse</option><option value='S002'>Moulding</option><option value='S003'>Production</option><option value='S090'>Finished Goods</option></select></td><td><input type='number' step='0.01' name='qty" + j + "' id='qty" + j + "' value='' size='5' onBlur='getPrice(" + j + ");'/></td>'<td><select id='reason" + j + "' name='reason" + j + "' disabled onChange='getCodes(" + j + ");'>"+ code + "</select><br/><div name='gl_cc" + j + "' id='gl_cc" + j + "' style='text-align:left'>You must choose + or - to be able to select reason.</div></td><td><textarea name='notes" + j + "' rows=3 cols=20></textarea></td>" );
    j++
    $('#tab_logic').append('<tr id="addr' + (i + 1) + '"></tr>');
    document.getElementById("item_count").value= i;
    i++;
  });
});
</script>

Ak odoslem len jednu polozku je to fajn. Ak ich odoslem 2 alebo viac take mi to hadze chybu otice: Undefined index: part_no1 in
kod ktory to spracovava

Kód: [Vybrat]


for ($j = 1; $j <= $i; $j++) {
        $clock_no = $_POST['clock_no'];
        $part_no = strtoupper($_POST['part_no' . $j . '']);
        echo $part_no;
        $qty = $_POST['qty' . $j . ''];
        $location = trim($_POST['location' . $j . '']);
        $reason = $_POST['reason' . $j . ''];
        $notes = $_POST['notes' . $j . ''];
        $notes = str_replace("'", "''", $notes);
        if (isset($_POST['gl_account' . $j . ''])) {
            $gl_account = $_POST['gl_account' . $j . ''];
        } else {
            $gl_account = '';
        }
        if (isset($_POST['cost_centre' . $j . ''])) {
            $cost_centre = $_POST['cost_centre' . $j . ''];
        } else {
            $cost_centre = '';
        }čo s tým? Preco sa to deje?

[Reklama]

[Kit]

Začal bych tímto:

Kód: [Vybrat]

<?php
var_dump($_POST);Zpravidla to odpoví na všechny podobné otázky.

[MichalPecko89]

Kit ok
Ak posielam jednu polozku je to fajn.

Kód: [Vybrat]

array (size=12)
  'item_count' => string '1' (length=1)
  'clock_no' => string '1132' (length=4)
  'plusminus1' => string '1' (length=1)
  'value1_id=' => string '' (length=0)
  'curr1' => string 'EUR' (length=3)
  'converted1' => string '' (length=0)
  'part_no1' => string 'ewre' (length=4)
  'location1' => string 'S001' (length=4)
  'qty1' => string '555' (length=3)
  'reason1' => string 'Stock Discrepancy' (length=17)
  'notes1' => string '' (length=0)
  'new' => string '' (length=0)toto je ked posielam 2

Kód: [Vybrat]

array (size=15)
  'item_count' => string '2' (length=1)
  'clock_no' => string '1132' (length=4)
  'location1' => string 'S002' (length=4)
  'reason1' => string 'Stock Check Errors' (length=18)
  'notes1' => string '' (length=0)
  'plusminus2' => string '1' (length=1)
  'value2_id=' => string '' (length=0)
  'curr2' => string 'EUR' (length=3)
  'converted2' => string '' (length=0)
  'part_no2' => string '52' (length=2)
  'location2' => string 'S001' (length=4)
  'qty2' => string '25' (length=2)
  'reason2' => string 'Free Issue' (length=10)
  'notes2' => string '' (length=0)
  'new' => string '' (length=0)Ked posielam 2  a viac tak sa stratia parametre s pevej ako je to mozne ked je to rovnaky kod? Ved je to uplne jednoduchy kusok kodu.

[Kit]

Zřejmě si ten form přepisuješ. Koukám, že tam máš dvakrát id="plusminus".

[Kit]

Proč tam máš tohle?

Kód: [Vybrat]

for ($j = 1; ...Obvykle používám foreach nebo aspoň počítám od nuly.

[Reklama]

[MichalPecko89]

Skusam oboje ale zda sa mi ze mi to vzdy ako keby odsekne prve data. Netusim preco.
Nepoviem keby to nefunguje s jednym ale ten da v poriadku, uz ked su dva tak to nejde.
vzdy zmizne

Kód: [Vybrat]

'plusminus1' => string '1' (length=1)
  'value1_id=' => string '' (length=0)
  'curr1' => string 'EUR' (length=3)
  'converted1' => string '' (length=0)
  'part_no1' => string 'ewre' (length=4)
ten var_dump($_POST); som dal na zaciatok este pred for loop

[MichalPecko89]

Zmenil som jednu jedinu vec a ide to

Kód: [Vybrat]

$('tr').find('input').prop('disabled',false)ale netusim co je pricina.

[Kit]

No jasně. Tímto příkazem jsi vždy odstavil předchozí input.